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x^2-290x=0
a = 1; b = -290; c = 0;
Δ = b2-4ac
Δ = -2902-4·1·0
Δ = 84100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{84100}=290$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-290)-290}{2*1}=\frac{0}{2} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-290)+290}{2*1}=\frac{580}{2} =290 $
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